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Resistors in Series/Parallel Combinations
Introduction
In this section we look at how to analyse circuits which contain resistors in series and parallel
combinations.
Identifying and Analysing Parallel Circuits
The figure below shows a basic circuit which contains a series-parallel combination of resistors.
The resistance from point A to point B is R1, the resistance from B to C
is the 
combination of R2 and R3 in parallel. The total circuit resistance
(from point A to C) is the series resistor R1 in combination with the parallel
components. A more complex example of a series-parallel resistor circuit is shown below
here the resistor R6 is in parallel with
the resistors R4 and
R5. Also the resistors R3, R2 andR1 form a parallel combination. It is also
clear that the two parallel combinations are in series with one another.
To calculate the total resistance of a series-parallel circuit we use the techniques we have
developed in the two previous sections. To illustrate the basic analysis procedures we will use
a couple of examples. First we consider the circuit below
and wish to calculate the total circuit resistance. The current will clearly pass through the 80 Ohm resistor before splitting into two components in the
parallel combination, at point A the parallel branch
currents will recombine and flow to the positive terminal. To calculate the total circuit resistance
first we work out the effective resistance of the parallel combination, using the method from the
previous section.
Rparallel = 1/(1/100 + 1/50) = 33.3
Ohms
Using this result we can redraw the circuit above as follows
The total circuit resistance can now be calculated by summing the two series resistances.
RT = 80 + 33.3 = 113.3
Ohms
Next we will examine the slightly more complex circuit below.
Using the same procedure as above we first work out the equivalent resistance of each of the
parallel combinations to get the effective resistance in series with R1. We begin
with the resistors R4 and R5
R5-4 = 1/(1/37 + 1/45) = 20.3
Ohms
Now we work out the resistance in each of the parallel branches. For the top branch the
resistance is equal to the sum of the resistors R2 andR3
R3-2 = 49 + 51 = 100
Ohms
for the bottom branch it is equal to the sum of the resistors R6 andR5-4
R6-5-4 = 75 + 20.3 = 95.3
Ohms
Now we are left with a circuit equivalent to the figure below
So all that is left is to work out the effective resistance of the parallel combination R6-5-4 and R3-2
R6-5-4-3-2 = 1/(1/100 + 1/95.3) = 48.8
Ohms
So the total circuit resistance is RT = 80 +
48.8 = 128.8 Ohms
The systematic approach we have introduced above can be used to work out the effective
resistance of any specific circuit. However if we know the voltage or current properties of the
circuit we can employ the same approach to calculate the unknowns. In the AC circuit analysis
section which follows we will look at circuits which contain resistors, capacitors and inductors
and use a very similar strategy to analyse the circuit response of these systems.
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